(x+1)^2/3+(x+1)^1/3-6=0

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Solution for (x+1)^2/3+(x+1)^1/3-6=0 equation: 


x in (-oo:+oo)

((x+1)^2)/3+((x+1)^1)/3-6 = 0

((x+1)^2)/3+(x+1)/3-6 = 0

((x+1)^2)/3+(x+1)/3+(-6*3)/3 = 0

(x+1)^2+x-6*3+1 = 0

x^2+3*x-18+2 = 0

x^2+3*x-16 = 0

x^2+3*x-16 = 0

x^2+3*x-16 = 0

DELTA = 3^2-(-16*1*4)

DELTA = 73

DELTA > 0

x = (73^(1/2)-3)/(1*2) or x = (-73^(1/2)-3)/(1*2)

x = (73^(1/2)-3)/2 or x = (-(73^(1/2)+3))/2

(x+(73^(1/2)+3)/2)*(x-((73^(1/2)-3)/2)) = 0

((x+(73^(1/2)+3)/2)*(x-((73^(1/2)-3)/2)))/3 = 0

((x+(73^(1/2)+3)/2)*(x-((73^(1/2)-3)/2)))/3 = 0 // * 3

(x+(73^(1/2)+3)/2)*(x-((73^(1/2)-3)/2)) = 0

( x+(73^(1/2)+3)/2 )

x+(73^(1/2)+3)/2 = 0 // - (73^(1/2)+3)/2

x = -((73^(1/2)+3)/2)

( x-((73^(1/2)-3)/2) )

x-((73^(1/2)-3)/2) = 0 // + (73^(1/2)-3)/2

x = (73^(1/2)-3)/2

x in { -((73^(1/2)+3)/2), (73^(1/2)-3)/2 }

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